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-0.5x^2+6x-7=0
a = -0.5; b = 6; c = -7;
Δ = b2-4ac
Δ = 62-4·(-0.5)·(-7)
Δ = 22
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{22}}{2*-0.5}=\frac{-6-\sqrt{22}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{22}}{2*-0.5}=\frac{-6+\sqrt{22}}{-1} $
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